Hi the list,
I'm on a problem since 2 days now and i don't know where to continu to
investigate ... notice i've started python 2 month ago and honestly, i
don't know if my problem is pywin32, or py2exe, or pyInstaller (same
behavior) or simply my code.
The problem is that i don't have any luck to make a simple Windows
Service when my python script
is compiled in a full standalone executable. I've tried different
version of python (2.4.4, 2.5.1 and 2.5.2) with latests version of
theses packages:
* python 2.5.2
py2exe-0.6.6.win32-py2.5.exe
pywin32-210.win32-py2.5.exe
* python 2.4.4
py2exe-0.6.6.win32-py2.4.exe
pywin32-210.win32-py2.4.exe
I'm on a basic Windows XP SP2, completely up-to-date.
Here is the code sample, but notice that the sample provided with
py2exe (samples\advanced\MyService.py), and the sample provided with
pyWin32 (win32\Demos\service\pipeTestService.py) got the same behavior
:
import win32service
import win32serviceutil
#import win32traceutil
import time
import sys
#at this point. We're ready to go.
#Put simply, a python windows service inherits from
win32serviceutils.ServiceFramework
#simply extending that class, sets up all you ever need to do.
class aservice(win32serviceutil.ServiceFramework):
_svc_name_ = "aservice"
_svc_display_name_ = "aservice - It Does nothing"
def __init__(self,args):
win32serviceutil.ServiceFramework.__init__(self,args)
self.isAlive = True
def SvcDoRun(self):
import servicemanager
while self.isAlive:
servicemanager.LogInfoMsg("aservice - is alive and well")
time.sleep(10) #perhaps must use win32.sleep(10) ?
servicemanager.LogInfoMsg("aservice - Stopped")
def SvcStop(self):
import servicemanager
servicemanager.LogInfoMsg("aservice - Recieved stop signal")
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
self.isAlive = False #this will make SvcDoRun() break the
while loop at the next iteration.
if __name__ == '__main__':
print "lets's start, args are : "
print sys.argv
win32serviceutil.HandleCommandLine(aservice) #this line sets it
all up to run properly.
Notice you can enable win32traceutil to see stdout. In this case, open
another Dos console an execute
python C:\Python2X\Lib\site-packages\win32\lib\win32traceutil.py
* Using python:
python myService.py -install: install the service as expected
python myService.py start: start the service as expected
python myService.py -remove: remove the service as expected
* Using pyInstaller compiled version
myService.exe -install : install the service as expected
myService.exe start : don't work
myService.exe -remove : remove the service as expected
pyInstaller 1.3 with python 2.4 : in the python win32traceutil window,
you can see that when you start the service using "myService.exe
start", myService.exe is launched twice !
Same behavior using pyInstaller trunk checkout with python 2.5.2
The error is " The service did not respond to the start or control
request in a timely fashion "
Replacing "myService.exe start" with "sc start aservice" output the same thing.
* Using py2exe compiled version
Every time, i've got
Connecting to the Service Control Manager
Traceback (most recent call last):
File "boot_service.py", line 173, in ?
pywintypes.error: (1063, 'StartServiceCtrlDispatcher', "Le processus de service
n'a pas pu se connecter au contr\xf4leur de service.")
---------------
I have Windows XP SP2 with latest updates and i didn't try on another
box (because i got only one ;)
I've tried lot's of different service code, install or remove always
work, start never
I saw some "if sys.frozen" in pywin32 so i know the code is a little
bit different when the program is an executable or when it's launched
using python command line, perhaps it can be a way to find the problem
if it's a pywin32 problem ..
Should be great if somebody can help me on this, thanks in advance,
Regards,
Franck
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