Hello,
When launching an app that opens a socket, windows Vista complains that
I have to accept it before it is launched and then that the firewall
accepts the opening of the port.
Is there a way to register my app to be launched by users without UAC
warning ?
Is there a way to open the port on the firewall inside the program or
its installer ?
Thanks.
_______________________________________________
python-win32 mailing list
python-win32@python.org
http://mail.python.org/mailman/listinfo/python-win32