Try using the normal file access functions, eg: open("file","r"), etc.
~G
On Mon, Feb 23, 2009 at 6:14 AM, venu madhav <venutaurus...@gmail.com> wrote:
> Hello all, I am writing an application where I need to open a shared file on
> a remote machine using python script. I tried using the following function:
> f = urllib.open("\\remote_machine\\folder1\\file1.doc") I also tried using
> class urllib.FancyURLopener(...) but didn't work. Can some one help me in
> this regard. Thank you in advance, Venu
>
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