OK, so I wrote my own InstallService:
--------------------------------------------------------------------------------
import sys, os, win32service
def InstallService(pythonClassFile, serviceName, displayName,
startType = None, errorControl = None, bRunInteractive = 0,
serviceDeps = None, userName = None, password = None,
exeArgs = None, description = None):
# Handle the default arguments.
if startType is None:
startType = win32service.SERVICE_DEMAND_START
serviceType = win32service.SERVICE_WIN32_OWN_PROCESS
if bRunInteractive:
serviceType = serviceType | win32service.SERVICE_INTERACTIVE_PROCESS
if errorControl is None:
errorControl = win32service.SERVICE_ERROR_NORMAL
pythonClassFile = os.path.abspath(pythonClassFile)
commandLine = '"%s" "%s"' % (sys.executable, pythonClassFile)
if exeArgs:
commandLine = commandLine + " " + exeArgs
hscm =
win32service.OpenSCManager(None,None,win32service.SC_MANAGER_ALL_ACCESS)
try:
hs = win32service.CreateService(
hscm,
serviceName,
displayName,
win32service.SERVICE_ALL_ACCESS, # desired access
serviceType, # service type
startType,
errorControl, # error control type
commandLine,
None,
0,
serviceDeps,
userName,
password)
if description is not None:
try:
win32service.ChangeServiceConfig2(hs,win32service.SERVICE_CONFIG_DESCRIPTION,description)
except NotImplementedError:
pass ## ChangeServiceConfig2 and description do not exist on
NT
win32service.CloseServiceHandle(hs)
finally:
win32service.CloseServiceHandle(hscm)
if __name__ == "__main__":
if len(sys.argv) > 1 and os.path.exists(sys.argv[1]):
InstallService(sys.argv[1], os.path.basename(sys.argv[1]),
os.path.basename(sys.argv[1]))
--------------------------------------------------------------------------------
Note that it doesn't try to register the class string. Seems to work:
$ python myinstallservice.py test2.py
$ sc query test2.py
SERVICE_NAME: test2.py
TYPE : 10 WIN32_OWN_PROCESS
STATE : 1 STOPPED
(NOT_STOPPABLE,NOT_PAUSABLE,IGNORES_SHUTDOWN)
WIN32_EXIT_CODE : 0 (0x0)
SERVICE_EXIT_CODE : 0 (0x0)
CHECKPOINT : 0x0
WAIT_HINT : 0x0
$ sc qc test2.py
[SC] GetServiceConfig SUCCESS
SERVICE_NAME: test2.py
TYPE : 10 WIN32_OWN_PROCESS
START_TYPE : 3 DEMAND_START
ERROR_CONTROL : 1 NORMAL
BINARY_PATH_NAME : "c:\UpLib\1.7.9\python\python.exe"
"c:\testrepo2\overhead\test2.py"
LOAD_ORDER_GROUP :
TAG : 0
DISPLAY_NAME : test2.py
DEPENDENCIES :
SERVICE_START_NAME : LocalSystem
$
Although I think I should be crunching those paths to the "short" form.
However, it doesn't start:
$ sc start test2.py
[SC] StartService FAILED 1053:
The service did not respond to the start or control request in a timely fashion.
$
Here's what's in test2.py:
--------------------------------------------------------------------------------
import win32serviceutil
import win32service
import win32event
import win32evtlogutil
import servicemanager
class MyService(win32serviceutil.ServiceFramework):
_svc_name_ = "test2.py"
_svc_display_name_ = "test2.py"
def __init__(self, args):
win32serviceutil.ServiceFramework.__init__(self, args)
self.hWaitStop = win32event.CreateEvent(None, 0, 0, None)
def SvcStop(self):
self.ReportServiceStatus(win32service.SERVICE_STOP_PENDING)
win32event.SetEvent(self.hWaitStop)
def SvcDoRun(self):
servicemanager.LogMsg(servicemanager.EVENTLOG_INFORMATION_TYPE,
servicemanager.PYS_SERVICE_STARTING,
(self._svc_name_, ""))
while True:
win32event.WaitForSingleObject(self.hWaitStop, 500)
servicemanager.Initialize()
servicemanager.PrepareToHostSingle(MyService)
win32serviceutil.HandleCommandLine(MyService)
--------------------------------------------------------------------------------
What am I missing here?
Bill
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