Thanx ! that really helpful and fast way. i just have lots of Bboxs to check thank you thank you :=) Barak
On 25 פברואר, 02:00, Chad Dombrova <[email protected]> wrote: > list comprehension: > > >>> a= [ 1.1111, 2.2222, 3.3333] > >>> [ round(x,2) for x in a] > [ 1.11, 2.22, 3.33] > > if you're rounding these values for the sake of printing them out then > you should use: > > >>> [ '%.02f' % x for x in a] > ['1.11', '2.22', '3.33'] > > On Feb 24, 2009, at 9:41 PM, barakooda wrote: > > > > > that what i did > > but there is function that deal automatically with list or touple ? > > that was my question basically > > > On 25 פברואר, 00:59, Chad Dombrova <[email protected]> wrote: > >> python to the rescue: > > >> >>> round( 1.24343, 2) > >> 1.24 > > >> On Feb 24, 2009, at 7:31 PM, barakooda wrote: > > >>> for example i have A=(1.2323,1.3232,1.454 > > >>> i`m looking for automate function that will output same A but with 2 > >>> decimal points less > > >>> the new A will be: > >>> 1.2,1.3,1.4) > > >>> i can do it manually but in my script it wont be fun at all :-) > >>> thank you !!! > > --~--~---------~--~----~------------~-------~--~----~ http://groups.google.com/group/python_inside_maya -~----------~----~----~----~------~----~------~--~---
