What is your alternative method?
Thanks,
Peter
On Apr 8, 11:29 am, Sylvain Berger <[email protected]> wrote:
> what would you suggest to use to check what type of component the current
> component is?
> let's say I have a mixed selection of faces, vertex, edges and polygon mesh
> and I want to split each type in different list...
>
> import pymel as pm
> sel = pm.selected()
> for i in sel:
> if i.nodeType() == 'mesh':
> print '%s is a polygon mesh' %i
> if i.nodeType() == 'meshVertex':
> print '%s is a polygon vertex' %i
> if i.nodeType() == 'meshEdge':
> print '%s is a polygon edge' %i
> if i.nodeType() == 'meshFace':
> print '%s is a polygon face' %i
>
> I found an alternative method, but I would like to know if this is possible
>
> Thanks
>
> On Wed, Apr 8, 2009 at 10:33 AM, Paul Molodowitch <[email protected]>wrote:
>
>
>
>
>
> > So, the reason is that 'nodeType' is intended to replicate
> > maya.cmds.nodeType() - ie, return the mel type name of a dgnode (ie,
> > something that you'd find in
> >http://download.autodesk.com/us/maya/2009help/Nodes/index.html)
>
> > Since a component isn't a dgNode, nodeType for components (and
> > attributes) returns the dg node type of the dg node it's attached to.
>
> > I can see why this might be confusing, so I added a note to the
> > docstring for nodeType.
>
> > - Paul
>
> > On Tue, Apr 7, 2009 at 11:52 AM, sberger <[email protected]> wrote:
>
> > > Hi, I am wondering why the nodeType() method of a vertex return mesh
> > > instead of meshVertex type?
>
> > > # run this code to repro
> > > sphere = pm.polySphere()[0]
> > > pm.select('%s.vtx[0:10]' %sphere, r=True)
> > > sel = pm.ls(sl=True, fl=True)
> > > for i in sel:
> > > print 'nodeType:', i.nodeType()
> > > print type(i)
>
> > > Thanks
>
> --
> They say, "Evil prevails when good men fail to act." What they ought to say
> is, "Evil prevails."
> Nicolas Cage as Yuri Orlov in Lord of War.
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