Hi
thanks for your idea ..
but print sys.modules.get('tempPython') ,
it will return as None .
I think maybe i made confuse , I want to get the file path of current file
which i am running
for eg: I am running a file called tempPython.py
inside this python file I want to get file path of tempPython.py and i want
to print it .
Is that clear ??
and i am sorry for my bad English:)
On Thu, Apr 23, 2009 at 2:08 PM, pierrotb <[email protected]> wrote:
>
> You can use this.
> sys.modules.get('idlelib')
> <module 'idlelib' from 'C:\Python25\Lib\idlelib\__init__.pyc'>
>
> On 23 avr, 09:51, Achayan <[email protected]> wrote:
> > Hi All
> >
> > I have doubt , is there any way to find a file path in python ??
> >
> > for eg: I have a file named as testPython.py and its saved in D:\Temp
> > While i am running the testPython.py i need to find from where is
> > getting sourced .
> > Is there any chance ??
> >
> > I got a information about __file__ but it will work only if we import
> > this script.
> > Without importing the file i need to find the file path.
> >
> > Any help :)
> >
> > Thanks
> >
> > O.S.K
> >
>
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