wonderful... thanks i didn't find that set class.It is freaking sweet! listA = [1,2,3] listB = [2,3,4,5] setB.difference(set(listA)) # Result: set([4, 5]) # setB.symmetric_difference(set(listA)) # Result: set([1, 4, 5]) #
This rock, exactly what I needed Thanks for the extremely quick answer On Thu, Jun 11, 2009 at 2:44 PM, chadrik <[email protected]> wrote: > > check out the builtin 'set' class > > -chad > > > > On Jun 11, 2009, at 11:38 AM, sberger wrote: > > > > > Hi guys, i would to know if there is already function in python to > > perform list booleans. > > > > For example, given those list > > listA = [1,2,3] > > listB = [2,3,4,5] > > > > performing these operation would give the result > > listB-listA would give [4,5] > > > > listA+listB would give [1,2,3,4,5] > > > > etc.. > > > > thanks > > > > > > > > -- They say, "Evil prevails when good men fail to act." What they ought to say is, "Evil prevails." Nicolas Cage as Yuri Orlov in Lord of War. --~--~---------~--~----~------------~-------~--~----~ http://groups.google.com/group/python_inside_maya -~----------~----~----~----~------~----~------~--~---
