Ah well, hope this is correct but I appear to be able to do that check like
this:
#Name starts with scene name.
re.match( name , filename , flags=0 )
#Scene has same extension
os.path.splitext( filename )[1] == ext
#Padding and prefix lengths match
re.search( r'%s%s%s\.' % ( seperator , '\w'*prefix , '\d'*padding ) , filename
, flags=0 )
#Prefix name matches
name = filename.rfind('.')
Pa = 3 # length of padding
Pr = 1 # length of prefix
name[ name - ( Pa + Pr ) : name - Pa ] == prefix
Feels a lot more 'lightweight' but please shout back with comments, I have no
idea if I'm using python expressionism right or not :)
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