Excellent! Thank you for the insight Andres. Much appreciated. On Thursday, May 29, 2014 3:21:01 PM UTC-4, Andres Weber wrote: > > You pretty much got it, you're missing a ws=True flag in your xform > command (that way we get the worldspace instead of the local space...just > in case the transforms are funkily nested). The last thing you're missing > is, getChildren() returns [] when it doesn't have children, but > mc.listRelatives() returns None. So the line in the if statement becomes: > if not mc.listRelatives(obj,children=True,type='transform'): > > On Wednesday, May 28, 2014 8:04:56 PM UTC-4, flaye wrote: >> >> Thanks Andres! That worked great. Now, regardless of the primary axis, it >> returns the correct length. >> >> By the way, I'm not too familiar with pymel (yet). Is there an equivalent >> to the code in Python proper? Specifically the getTranslation & getChildren >> commands? >> >> I've tried this, but I get errors: >> >> from math import * >> def dist (objA, objB): >> Ax,Ay,Az=mc.xform(objA,q=1,t=1) >> Bx,By,Bz=mc.xform(objB,q=1,t=1) >> return sqrt(pow((Ax-Bx),2)+pow((Ay-By),2)+pow((Az-Bz),2)) >> >> def lenJointChain(obj,len=0): >> print obj >> if mc.listRelatives(obj,children=1)==[]: >> return len >> else: >> child=mc.listRelatives(obj,children=1,type='transform')[0] >> return lenJointChain (child, len=len+dist(obj,child)) >> >> lenJointChain(mc.ls(sl=True)[0]) >> >> >> Thanks. >> >> On Wednesday, May 28, 2014 5:15:12 PM UTC-4, Andres Weber wrote: >>> >>> I'm not really sure why you're doing it the way you're doing it... >>> This is how I solved it quickly (There's better ways but I'm lazy and I >>> didn't want to keep working on it.) Just a simple recursive function. >>> >>> def dist( objA, objB ): >>> >>> Ax, Ay, Az = objA.getTranslation(space="world") >>> >>> Bx, By, Bz = objB.getTranslation(space="world") >>> >>> return ( (Ax-Bx)**2 + (Ay-By)**2 + (Az-Bz)**2 )**0.5 >>> >>> def lenJointChain(obj,len=0): >>> >>> if obj.getChildren()==[]: >>> >>> return len >>> >>> else: >>> >>> child=obj.getChildren(type='transform')[0] >>> >>> return lenJointChain(child, len=len+dist(obj,child)) >>> >>> lenJointChain(pm.ls(sl=True)[0]) >>> >>> >>> >>> On Wednesday, May 28, 2014 3:18:13 PM UTC-4, flaye wrote: >>>> >>>> >>>> >>>> # Find the full length of the chain >>>> sel=[] >>>> sel=mc.ls(sl=True) >>>> length = 0 >>>> for i in range(1, len(sel)): >>>> length += abs(mc.getAttr(sel[i]+'.tx')) >>>> >>>> print length >>>> >>>> >>>> The above code will provide the correct answer, on the condition that >>>> the primary axis of the joints (in this case, X) is known. >>>> >>>> I've also tried using the MVector function, but unfortunately the >>>> numbers are off >>>> >>>> import maya.api.OpenMaya as om #for api 2.0 >>>> sel=[] >>>> sel=mc.ls(sl=True) >>>> >>>> startjnt=sel[0] >>>> numjnts=len(sel) >>>> length=0 >>>> for i in range(0,numjnts-1): >>>> >>>> currentjnt=sel[i] >>>> >>>> nextjnt=mc.listRelatives(currentjnt,children=1)[0] >>>> >>>> print currentjnt,nextjnt >>>> >>>> t1=mc.xform(currentjnt,q=1,t=1) >>>> t2=mc.xform(nextjnt,q=1,t=1) >>>> >>>> v1=om.MVector(t1) >>>> v2=om.MVector(t2) >>>> >>>> dist=om.MVector(v2-v1).length() #equivalent to MEL's mag? >>>> length+=dist >>>> print length >>>> >>>> >>>> any ideas? Thanks. >>>> >>>>
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