Though this is probably not particularly useful for the problem the OP’s
was having, which is that lists in Python are *mutable*.
Meaning that, when you pass a list into a function, changes you make to it
are also made to the original list you passed in. If you’re familiar with
C++, then you can think of the list you pass as being passed by reference.
def append(a, b):
a.append(b)
my_list = ["Hello"]
append(my_list, "World")
print(" ".join(my_list))# Hello World
In order to pass a list, and *not* modify it, you can do what Alok
suggested, which is to make a copy of the list inside of the function.
def append(a, b):
copy = a[:]
copy.append(b)
my_list = ["Hello"]
append(my_list, "World")
print(" ".join(my_list))# Hello
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