On Wed, May 1, 2019 at 9:16 AM kiteh <kiteh.0...@gmail.com> wrote:
> Hi all,
>
> I am trying to do a 'skimming' or reduction method in dictionaries in
> which it will returns me a set of results from a given set of condition.
>
> However my current method is more of an additive where it will simply
> lists me any items that fulfills any one of the condition.
>
>
> Currently while it seems to be not working if there is only one key and
> one list item..
>
> # Give me items that are menuA/a100 + menuB/b100, or menuA/a100 +
> menuB/b200
> conditions = {'menuA':['a200']}
>
> my_items = [
> {'item01' : {'menuA': ['a100'], 'menuB': ['b200']}},
> {'item02' : {'menuA': ['a200'], 'menuB': ['b200'], 'menuC' :
> ['c100']}},
> {'item03' : {'menuA': ['a100'], 'menuB': ['b200']}},
> {'item04' : {'menuA': ['a100', 'a200']}},
> {'item05' : {'menuB': ['b100'], 'menuC': ['c100']}}
> ]
>
> result = []
>
> for m in my_items:
> for mk, mv in m.items():
> all_conditions_met = len(conditions) == len(mv) #False
> for condition in conditions:
> if condition in mv:
> all_conditions_met &= bool((set(mv[condition]) &
> set(conditions[condition])))
>
> ###############
> # Tried the following but it will fail if given condition
> # eg. conditions = {'menuA': ['a100', 'a200'], 'menuB':
> ['b200']}
> # where it should return me ['item01', 'item03'] but it gives
> me [] instead...
>
> # all_conditions_met &= bool((set(mv[condition]) &
> set(conditions[condition]))) & (len(mv[condition]) ==
> len(conditions[condition]))
> ###############
>
> else:
> all_conditions_met = False
> break
> if all_conditions_met:
> result.append(mk)
>
> print result # 'item04'
>
>
> In my above example, given the condition {'menuA':['a200']}, it should not
> be returning me any results as there are no items that consists only of
> {'menuA':['a200']} but yet it return me an item - closest to the given
> condition…
>
>
> The idea behind this is to simply returns me items based on the conditions.
>
>
> Could someone kindly share some insights on this matter?
>
First I would like to try and get clarification on exactly what you intend
your conditions to mean. Given:
conditions = {'menuA': ['a100', 'a200'], 'menuB': ['b200']}
I can assume from your example that an item must contain all keys of the
condition.
But for the values of each condition, is the item supports to contain all
of the condition values, or just any of the condition values. This will
determine what kind of testing you really need to be doing.
Can you also explain what your goal is between the outcome of your two
variations:
all_conditions_met &= bool((set(mv[condition]) &
set(conditions[condition])))
and
all_conditions_met &= bool((set(mv[condition]) &
set(conditions[condition]))) \
& (len(mv[condition]) == len(conditions[condition]))
The first variation does perform the "has ANY of the condition values"
check, while the second is performing a "has ALL of the condition values"
check. The second is also basically equivalent to doing the shorter:
set(mv[condition] == set(conditions[condition])
Where are you actually stuck, between those two variations of the condition
test?
- Justin
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