Let me check if I got..
If I:
1) store the matrix of the B ("ORIGINAL_B_pos") (before parenting to A)
2) parent B to A
3) move A (which will bring B to another place, to "NEW_B_pos")
4) unparent B (so B will go back to "ORIGINAL_B_pos" )
5) apply matrix in B (after this 5th step, B will go to "NEW_B_pos" ?)
Em qua., 17 de mar. de 2021 às 17:35, tomas mikulak <mikulakto...@gmail.com>
escreveu:
> and if you just use variable to save world matrix of parented B and after
> unparent just use data. Still guessing, don't know how slow it might be
>
> st 17. 3. 2021 o 21:32 João Victor <joaovictor...@gmail.com> napísal(a):
>
>> thanks a lot for the suggestion Tomas!
>> but I can´t use CMDS for parenting the new "helper locator", because I
>> am looking for reduce the time of the loop.. and it have to be made about
>> 30k times in the loop. For this reason I am trying to use the api instead
>> of CMDS. :)
>>
>> Em quarta-feira, 17 de março de 2021 às 17:25:33 UTC-3, tomas mikulak
>> escreveu:
>>
>>> Hi,
>>> I am not into API yet, but what if you also parented a locator under A
>>> with same position and rotation as B and after unparenting B just set it's
>>> transforms according to locator still under A
>>> Bad?
>>>
>>> tomas
>>>
>>> st 17. 3. 2021 o 21:20 João Victor <joaovi...@gmail.com> napísal(a):
>>>
>>>> Hi guys, could somebody help me in a doubt?
>>>>
>>>> I am trying to parent B to A, then move A, then unparent B. But at the
>>>> end of these operations, B can´t return to his original position, he must
>>>> keeps where A brought him.
>>>> How can I do that in the API?
>>>>
>>>> My current code is:
>>>>
>>>> *q1 = getMObject("A")*
>>>> *q2 = getMObject("B")*
>>>>
>>>> *p = new_om.MFnDagNode(q1)*
>>>> *p.addChild(q2)*
>>>>
>>>> *u = new_om.MDagModifier()*
>>>>
>>>> *u.reparentNode(q2) # here B returns to original position, thats the
>>>> problem*
>>>> *u.doIt()*
>>>>
>>>> Thanks a lot!
>>>>
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