Rayme,
This sounds like a Linked List system...
I was not able to find quickly a linked list module, but
searching by "trees" at the Vaults produced a R/B tree...
http://newcenturycomputers.net/projects/rbtree.html
I've been out of touch, I have not heard about the Red/Black
balanced tree algorithm...
Hmm... But take a look and see if it meets your
requirements...
But take a look at your implementation, if your just
trying to make a linked list, you could just use a
standard python list....
- Benjamin
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED] On Behalf Of Rayme Jernigan
> Sent: Wednesday, January 12, 2005 12:53 PM
> To: pythonmac-sig@python.org
> Subject: [Pythonmac-SIG] self-instantiating instances in pyhton
>
>
> Hi,
>
> I'm looking for a language to abuse for a project I'm working on. I
> know a little Python, but I do not know if it can do this:
> I'd like to
> define some class "N" that instantiates objects that can instantiate
> fresh new objects of that same class... without external controller
> code.
>
> You could use this capability, for example, to generate a red-black
> tree-type data structure that implicitly instantiates a new node for
> each new input d1, d2, d3... so on. The algorithm for each node could
> be:
>
> -- Toggle downstream L/R pointer
> -- If no node there, instantiate one and link to it
> -- if a node is there, pass the datum to it
>
> The execution sequence as the tree builds itself out might look
> something like this:
>
> 1. n0 = N(d0) # new instance of N
> # (downstream pointer default = "Left")
> # (the first input data, d0, is
> instantiated in node n0)
> # nodes: n0
>
> 2. n0.send(d1) # toggle n0's downstream pointer to "Right"
> # on n0 there is no downstream node
> right so instantiate a new
> linked node right n1 with d1
> # nodes: n0,n1
>
> 3. n0. send(d2) # toggle n0's downstream pointer "Left"
> # in n0 there is no downstream node
> left so instantiate n2 with d2
> # nodes: n0,n1,n2
>
> 4. n0. send(d3) # toggle n0's downstream pointer "Right"
> # there exists a downstream node right,
> n1, so send d3 there
> # toggle n1's downstream pointer "Right"
> # in n1 there is no downstream node
> right so instantiate n3 with d3
> # nodes: n0,n1,n2,n3
>
> 5. n0. send(d4) # toggle n0's downstream pointer "Left"
> # there exists a downstream node left,
> n2, so send d4 there
> # toggle n2's downstream pointer "Right"
> # in n2 there is no downstream node
> right so instantiate n4 with d4
> # nodes: n0,n1,n2,n3,n4
>
> 6. n0.send(d5) # toggle n0's downstream pointer "Right"
> # there exists a downstream node right,
> n1, so send d5 there
> # toggle n1's downstream pointer "Left"
> # in n1 there is no downstream node
> left so instantiate n5 with d5
> # nodes: n0,n1,n2,n3,n4,n5
>
> 7. n0.send(d6) # So on...
> # ...
>
>
> Any thoughts about how to do this in Python appreciated. Possible at
> all? Thanks in advance,
>
> -Rayme.
>
> _______________________________________________
> Pythonmac-SIG maillist - Pythonmac-SIG@python.org
> http://mail.python.org/mailman/listinfo/pythonmac-sig
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