Henning Hraban Ramm wrote:
I'm looking for a better algorithm...
This is probably as terse as it gets:
def bool2cm0k(lst):
"""Converts a list of booleans to a CMYK color string,
e.g. [True, False, False, True] to 'C00K'
"""
return ''.join([b and c or '0' for b, c in zip(lst, 'CMYK')])
def cm0k2bool(s):
"""Converts a CMYK color string to a list of booleans,
e.g. 'CM0K' to [True, True, False, True]
"""
return [c1 == c2 for c1, c2 in zip(s, 'CMYK')]
print bool2cm0k([True, False, False, True]) # --> C00K
print cm0k2bool('CM0K') # --> [True, True, False, True]
HTH
has
--
http://freespace.virgin.net/hamish.sanderson/
_______________________________________________
Pythonmac-SIG maillist - Pythonmac-SIG@python.org
http://mail.python.org/mailman/listinfo/pythonmac-sig
