On Mon, Dec 18, 2006 at 11:11:27PM +0000, Hamish Allan wrote:
> itunes = app('iTunes')
> x = itunes.sources.first.playlists[its.name.contains('MyName')]
>
> This code fetches any playlists containing the string 'MyName'. But I
> want an exact match. Using 'equals' rather than 'contains' doesn't
> work.
You just use '==' instead.
In [4]: itunes.sources.first.playlists[its.name == 'Stations']()
Out[4]:
[app(u'/Applications/iTunes.app').sources.ID(41).user_playlists.ID(1936)]
But in this case, you don't need to.
In [6]: itunes.sources.first.playlists['Stations']()
Out[6]: app(u'/Applications/iTunes.app').sources.ID(41).user_playlists.ID(1936)
Most objects support multiple reference forms, as you'll see if you
look at their documentation.
> How do I find out which operations its.name supports? And more
> generally, what is possible in other similar situations with different
> objects?
Use .help(). So, for example, you can see that the playlists can be
referenced by index, name or ID:
In [7]: itunes.sources.first.playlists.help()
==============================================================================
Appscript Help (-t)
Reference: app(u'/Applications/iTunes.app').sources.first.playlists
------------------------------------------------------------------------------
Description of reference
Element: playlists -- by index, name, id
[...]
Note the reference forms above.
It also helps to view the scripting dictionary, either using
appscript's tools for doing so in a Web browser, or just with Script
Editor (as I normally do).
> I also want to do what the following code suggests:
>
> x = itunes.sources.first.playlist_folders[its.name.equals('MyFolder')]
You want 'folder_playlists' not 'playlist_folders'. So again it's
pretty simple:
In [15]: itunes.sources.first.folder_playlists['Statistics']()
Out[15]:
app(u'/Applications/iTunes.app').sources.ID(41).folder_playlists.ID(122340)
> y = itunes.sources.first.playlists[its.parent.equals(x)]
Unfortunately here you run into a problem, as Apple didn't fully
implement terminology for 'folder playlists', but you can view the
scripting dictionary to figure it out. 'parent', while a property of
playlists, isn't always set. So the only thing I could figure out was
to iterate through them in Python:
In [45]: stats_id = itunes.folder_playlists['Statistics'].id()
In [46]: [p for p in itunes.user_playlists() if p.parent.exists()
....: and p.parent.id() == stats_id]
Out[46]:
[app(u'/Applications/iTunes.app').sources.ID(41).user_playlists.ID(1032),
app(u'/Applications/iTunes.app').sources.ID(41).user_playlists.ID(1158),
app(u'/Applications/iTunes.app').sources.ID(41).user_playlists.ID(1060)]
--
Nicholas Riley <[EMAIL PROTECTED]> | <http://www.uiuc.edu/ph/www/njriley>
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