When GDB is connected with qemu-1.1.0(target x86_64-softmmu), it is not possible to debug it. (Bug#640213)
The reason for the cause is that the correspondence of CPU register and the register value seen on the GDB side is incorrect. The evasion of the problem is possible by the replacement of the cpu_ gdb_read_register() of qeqemu-1.1.0/gdbstub.c with the cpu_gdb_ read_register() of qemu-0.10.6/gdbstub.c. What is the change intention of this source? Qemu：qemu-1.1.0 GDB ：6.8-27.el5 - Qemu start option ./qemu-system-x86_64 -m 2048 hda.img -machine pc-1.0 -L ./pc-bios/ -monitor pty -s -S - CPU register dump from Qemu console (qemu) info registers EAX=00007480 EBX=00000350 ECX=00000053 EDX=000001f0 ESI=000003f6 EDI=0000015a EBP=00074800 ESP=000002ec EIP=0000e8f9 EFL=00000046 [---Z-P-] CPL=0 II=0 A20=1 SMM=0 HLT=0 ES =7480 00074800 0000ffff 00009300 CS =f000 000f0000 0000ffff 00009e00 SS =9f40 0009f400 0000ffff 00009300 DS =9f40 0009f400 0000ffff 00009300 FS =0000 00000000 0000ffff 00009300 GS =0000 00000000 0000ffff 00009300 LDT=0000 00000000 0000ffff 00008200 TR =0000 00000000 0000ffff 00008b00 GDT= 00009090 00000027 IDT= 00000000 000003ff :::: - CPU register dump from GDB (gdb) info registers eax 0x76a0 30368 ecx 0xe8f9 59641 edx 0x46 70 ebx 0xf000 61440 esp 0x9f40 0x9f40 ebp 0x9f40 0x9f40 esi 0x76a0 30368 edi 0x0 0 eip 0x0 0 eflags 0x0 [ ] cs 0x0 0 ss 0x0 0 ds 0x0 0 es 0x0 0 fs 0x0 0 gs 0x0 0 -- E.Furukawa
