Hi there:

Sorry to post this problem a second time, for I thought maybe the
question is not descripted clearly.

I'm studying the execution details of multi-vcpu in TCG mode.

The vcpus in TCG mode are executed one by one in a sequencial way,
according to some articles about Qemu.

I read the function [tcg_exec_all] in Qemu 1.3.0 as bellow, but the
implementation is not as expected.

[tcg_exec_all] will finally call [cpu_exec] to excute a loop to excute
the TBs in code cache

So,how does these functions control the running time of each VCPU?

That is,when will the execution of one VCPU return, in order to execute
the next_cpu in the loop of [tcg_exec_all].

Using alarm timer or other methonds?

        staticvoidtcg_exec_all(void)
        {
        intr;

        /* Account partial waits to the vm_clock. */
        qemu_clock_warp(vm_clock);

        if(next_cpu==NULL){
        next_cpu=first_cpu;
        }
        *for(;next_cpu!=NULL&&!exit_request;next_cpu=next_cpu->next_cpu){*
        CPUArchState*env=next_cpu;
        CPUState*cpu=ENV_GET_CPU(env);

        qemu_clock_enable(vm_clock,
        (env->singlestep_enabled&SSTEP_NOTIMER)==0);

        if(cpu_can_run(cpu)){
        ***r****=****tcg_cpu_exec**(**env**);*
        if(r==EXCP_DEBUG){
        cpu_handle_guest_debug(env);
        break;
        }
        }elseif(cpu->stop||cpu->stopped){
        break;
        }
        }
        exit_request=0;
        }

Yours
Puck

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