From: Paolo Bonzini <pbonz...@redhat.com>
The problem is introduced by commit 2332616 (exec: Support 64-bit
operations in address_space_rw, 2013-07-08). Before that commit,
memory_access_size would only return 1/2/4.
Since alignment is already handled above, reduce l to the largest
power of two that is smaller than l.
Cc: qemu-sta...@nongnu.org
Reported-by: Oleksii Shevchuk <alx...@gmail.com>
Tested-by: Oleksii Shevchuk <alx...@gmail.com>
Signed-off-by: Paolo Bonzini <pbonz...@redhat.com>
(cherry picked from commit 098178f2749a63fbbb1a626dcc7d939d5cb2bde7)
Signed-off-by: Michael Roth <mdr...@linux.vnet.ibm.com>
---
exec.c | 3 +++
1 file changed, 3 insertions(+)
diff --git a/exec.c b/exec.c
index 3ca9381..394f7e2 100644
--- a/exec.c
+++ b/exec.c
@@ -1928,6 +1928,9 @@ static int memory_access_size(MemoryRegion *mr, unsigned
l, hwaddr addr)
if (l > access_size_max) {
l = access_size_max;
}
+ if (l & (l - 1)) {
+ l = 1 << (qemu_fls(l) - 1);
+ }
return l;
}
--
1.7.9.5
