For a 64-bit ILP32 host, aligning to sizeof(long) is not enough.
Guess the minimum for any host is 8, as that covers uint64_t.
Qemu doesn't use a host long double or host vectors, except in
extremely limited circumstances.
Fixes a bus error for a sparc v8plus host.
Signed-off-by: Richard Henderson <r...@twiddle.net>
---
tcg/tcg.h | 5 ++++-
1 file changed, 4 insertions(+), 1 deletion(-)
diff --git a/tcg/tcg.h b/tcg/tcg.h
index da78721a0d..17b7750ee6 100644
--- a/tcg/tcg.h
+++ b/tcg/tcg.h
@@ -762,7 +762,10 @@ static inline void *tcg_malloc(int size)
{
TCGContext *s = &tcg_ctx;
uint8_t *ptr, *ptr_end;
- size = (size + sizeof(long) - 1) & ~(sizeof(long) - 1);
+
+ /* ??? This is a weak placeholder for minimum malloc alignment. */
+ size = QEMU_ALIGN_UP(size, 8);
+
ptr = s->pool_cur;
ptr_end = ptr + size;
if (unlikely(ptr_end > s->pool_end)) {
--
2.13.3
