Hello people!
I'm not able to boot any guest that sets a virtio block device like:
(branch master)
[PPC64]
qemu-system-ppc64 -cpu POWER8 -nographic -vga none -m 4G -M
pseries,accel=kvm,kvm-type=PR -drive file=disk.qcow2,if=virtio
QEMU Starting
Build Date = Dec 18 2017 13:08:00
FW Version = git-fa981320a1e0968d
Press "s" to enter Open Firmware.
Populating /vdevice methods
Populating /vdevice/vty@71000000
Populating /vdevice/nvram@71000001
Populating /vdevice/v-scsi@71000002
SCSI: Looking for devices
8200000000000000 CD-ROM : "QEMU QEMU CD-ROM 2.5+"
Populating /pci@800000020000000
00 0000 (D) : 1af4 1000 virtio [ net ]
Aborted
[x86]
qemu-system-x86_64 -m 4G -enable-kvm -drive file=util.qcow2,if=virtio
Running QEMU with GTK 2.x is deprecated, and will be removed
in a future release. Please switch to GTK 3.x instead
[1] 5282 abort
[Cause]
The commit 4fe6d78b2e introduces the
...
kvm_mem_ioeventfd_del(...) {
...
r = kvm_set_ioeventfd_mmio(fd, ...
if (r < 0) {
abort();
}
+ if (e->cleanup) {
+ e->cleanup(e);
+ }
}
For some reason, not yet clear to me, cleanup() calls the same
kvm_mem_ioeventfd_del again and again until kvm_set_ioeventfd_mmio
returns < 0 and abort().
I was going to send a patch to revert that 'if ()' but I think it could
cause a regression. What do you guys think?
Thanks,
Jose Ricardo Ziviani
