On 02/23/2018 06:18 AM, Peter Maydell wrote:
>> +    mm = (mm & 0xff) * (-1ull / 0xff);
> What is this expression doing? I guess from context that it's
> replicating the low 8 bits of mm across the 64-bit value,
> but this is too obscure to do without a comment or wrapping
> it in a helper function with a useful name, I think.

I do have a helper now -- dup_const.  I thought I'd converted all of the uses,
but clearly missed one/some.


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