On Fri 10 Aug 2018 08:26:39 AM CEST, Leonid Bloch wrote:
> Signed-off-by: Leonid Bloch <lbl...@janustech.com>
> ---
> docs/qcow2-cache.txt | 16 +++++++++++-----
> qemu-options.hx | 9 ++++++---
> 2 files changed, 17 insertions(+), 8 deletions(-)
>
> diff --git a/docs/qcow2-cache.txt b/docs/qcow2-cache.txt
> index 8a09a5cc5f..0f157d859a 100644
> --- a/docs/qcow2-cache.txt
> +++ b/docs/qcow2-cache.txt
> @@ -97,12 +97,15 @@ need:
> l2_cache_size = disk_size_GB * 131072
> refcount_cache_size = disk_size_GB * 32768
>
> -QEMU has a default L2 cache of 1MB (1048576 bytes) and a refcount
> -cache of 256KB (262144 bytes), so using the formulas we've just seen
> -we have
> +With the default cluster size, to cover each 8 GB of the virtual image
> +size, 1MB of L2 cache is needed:
>
> - 1048576 / 131072 = 8 GB of virtual disk covered by that cache
> - 262144 / 32768 = 8 GB
> + 65536 / 8 = 8192 = 8 GB / 1 MB
Where does this 65536 / 8 come from? The line that you changed follows
directly from the formula immediately before that paragraph:
l2_cache_size = disk_size_GB * 131072
that is
l2_cache_size / 131072 = disk_size_GB
1048576 / 131072 = 8 GB
Berto
