I believe you can do it this way (as I'm experimenting with this very
thing). Of course - if you have very small polygons with even smaller
polygons this wouldn't work.
Select features using an expression and let your expression be $area <
square units you are looking for.
I wanted to select everything in my layer less than 10 acres (I am
working in Feet) so I entered $area < 435600 and have quite a few
polygons selected now. I am checking to make sure it has done what I
wanted.
Hope this helps - I'm pretty sure there is a more elegant solution than
$area - but so far this works for me.
Randy
On 04/19/2015 12:38 PM, Giacomo Fontanelli wrote:
Hello forum
this post is similar to my last one, but not totally the same.
Thank you for making me know the Sieve filter.
I have a vector layer.
I have some polygons that apparently seem to be lying on bigger
polygons and totally included on this, but if you delete the small
ones they produce holes on the big polygons with the same dimension
and shape of the small polygons.
Well: this is the result I'd like to obtain, I mean I would like to
automatically delete the smaller polygons producing the described holes.
How can I do this?
Thank you very much
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Randal Hale
North River Geographic Systems, Inc
http://www.northrivergeographic.com
423.653.3611 rjh...@northrivergeographic.com
twitter:rjhale http://about.me/rjhale
http://www.northrivergeographic.com/introduction-to-quantum-gis
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