Thank you, Jorge :)
> Am 09.04.2020 um 14:15 schrieb Jorge Gustavo Rocha <[email protected]>: > > > Hi Christoph, > > You can use an QgsExpression [1] to filter features from that layer. > > expr = QgsExpression( " ... " ) > layer.getFeatures( QgsFeatureRequest( expr ) ) > > Regards, > > Jorge Gustavo > > [1] https://qgis.org/pyqgis/3.2/core/Expression/QgsExpression.html > > On 09/04/20 12:37, Christoph Jung wrote: >> Hello everyone, >> >> I have a question concerning PyQGIS. Imagine there is a point layer accessed >> via QgsVectorLayer, i.e. no matter which data source it is. Is it possible >> to query this layer to get the point object with the highest/lowest x-value >> in its geometry (similar to max-/min-aggregate functions in SQL)? Or do I >> have to iterate over all objects and compare the values by my own? >> >> Sincerely, >> Christoph >> _______________________________________________ >> Qgis-user mailing list >> [email protected] >> List info: https://lists.osgeo.org/mailman/listinfo/qgis-user >> Unsubscribe: https://lists.osgeo.org/mailman/listinfo/qgis-user > -- > > Geomaster > Jorge Gustavo Rocha | Software Engineer > e: [email protected] | m: +351 910 333 888 > g: 41.54094,-8.40490 | v: 510 906 109 > a: Rua António Cândido Pinto, 67, 4715-400 Braga > _______________________________________________ > Qgis-user mailing list > [email protected] > List info: https://lists.osgeo.org/mailman/listinfo/qgis-user > Unsubscribe: https://lists.osgeo.org/mailman/listinfo/qgis-user
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