Hi,
Open the vector file, open the field calculator, create a new field with
floats. Cut and paste this formula.
(atan((xat(-1)-xat(0))/(yat(-1)-yat(0)))) * 180/3.14159 + (180
*(((yat(-1)-yat(0)) < 0) + (((xat(-1)-xat(0)) < 0 AND (yat(-1) - yat(0))
>0)*2)))
I think the new way to call the x of first node is: $x_at(0) and not
xat(0) but the above works.
There must be an easier way ...
NIcolas
On 2021-01-09 2:46 a.m., Alejandro Fernandez "Al" Tongco wrote:
Thanks Nicolas for your time.
I'm trying to use both stand-alone SAGA (Snap Points to Polygons) to
produce the shortest line and QGIS to figure out the line angle
(line_interpolate_angle). As of now, I'm successful on the former but
not on the latter yet. I'll keep on trying...
*Alejandro Fernandez "Al" Tongco*
On Wednesday, December 30, 2020, 11:47:08 PM GMT+8, Nicolas Cadieux
<[email protected]> wrote:
Hi,
You can use the saga tool snap points to lines found in the
processing toolbox. Then ask for the option to create the distance
line (moves) and not the new points. From that new line file, you can
find the angle (azimut) of the line using an expression using the
field calculator.
https://docs.qgis.org/3.16/en/docs/user_manual/working_with_vector/functions_list.html#line-interpolate-point
<https://docs.qgis.org/3.16/en/docs/user_manual/working_with_vector/functions_list.html#line-interpolate-point>
Nicolas Cadieux
https://gitlab.com/njacadieux <https://gitlab.com/njacadieux>
Le 30 déc. 2020 à 02:13, Alejandro Fernandez "Al" Tongco
<[email protected]> a écrit :
Hello qgis users,
I need help how to calculate shortest length and angle of line
connecting a point and an area feature. I'm using QGIS 3.16 in
Windows 10.
Thank you in advance,
Al
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--
Nicolas Cadieux
https://gitlab.com/njacadieux
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