Thanks Til,
Or even better:
proto.func = function() {
superclass.func.call(this);
return 'In derived class';
}
In this way, we don't need to know the name of the superclass.
If the documentation were a wiki, I would have updated
http://old.qooxdoo.org/documentation/inheritance
Til Schneider schrieb:
>> proto.func = function() {
>> // How can I call here BaseClass.func()?
>> return 'In derived class';
>> }
>>
>
> BaseClass.func.call(this, param1, param2);
>
>
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