> I need to replace a qooxdoo (0.7.x) function from 'outside' (i.e. 
> without modifying the qooxdoo source itself.
> In addition, I want to be able to call the original function from 
> within the replacement and, of course, keep the this variable 
> intact.

Use qx.class.patch. Use this.base(arguments) for the base function in the
patch. See also http://bugzilla.qooxdoo.org/show_bug.cgi?id=323 and look
at frontend/application/testrunner/source/class/testrunner/test/Mixin.js

Hugh

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