Alexander Back wrote:
> Hi Kenny,
> 
> Kenneth Tilton wrote:
>> I tried simply adding the simplest splitpane demo to the widget where I 
>> eventually will be splitting two of my widgets. The starting point:
>>
>>   addSplitPaneTwoFlexSimple : function()
>>      {
>>        var splitpane = new qx.ui.splitpane.Pane("horizontal");
>>        splitpane.setWidth(400);
>>        splitpane.setHeight(60);
>>        splitpane.setDecorator("main");
>>        this.getRoot().add(splitpane, {left:20, top:20});
>>
>>        // Left
>>        var leftWidget = new qx.ui.form.TextArea("Flex:1");
>>        leftWidget.setDecorator(null);
>>        leftWidget.setWrap(true);
>>        splitpane.add(leftWidget, 1);
>>
>>        // Right
>>        var rightWidget = new qx.ui.form.TextArea("Flex:2");
>>        rightWidget.setDecorator(null);
>>        rightWidget.setWrap(true);
>>        splitpane.add(rightWidget, 2);
>>      },
> If I simply paste your snippet into the playground application 
> everything is working fine. Could you please provide the code for the 
> "control"? Maybe we can take a look at this part and find a solution.
> 
>> I had to yank the getRoot(). In general, btw, I wish the demos were more 
>> conducive to cut/paste. I have run into this before where the code 
>> assumed a distinct application (but truth be told in this case I am not 
>> sure why the demo needs a getRoot either). Anyway...
> Good point.
> Each demo is a full qooxdoo application, that's the reason why they need 
> to use "getRoot".

Maybe you could always drop in one widget deep so demos will plug and 
play out into arbitrary nodes in someones app? Just a thought.

Meanwhile...

> 
>> Now I get the error "At least one child in control <the guy to which I 
>> added the splitpane> requires a layout, but no one was defined!".
>>
>> Immediately after the code to add the splitpane I test hasLayoutChildren 
>> on the same guy and it is successful.
> Could you just send over more code to look at? :-)

That was it! :) You reminded me that that error message "one child of X 
needs a layout" is issued when I neglect to give X a layout (which 
layout had gotten chopped when hacking it in the splitpane.

thx, ken

ps. If my understanding is correct, the error might better be "If X is 
not given a layout,..." k

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