OK, thanks to you, it is clearer but still have things I don't
understand :
I loop throw my widgets and
qx.dev.Debug.debugObject(widget.getDecorator()).
The output show things like input, button, table but nothing like
Uniform, Single, ... (note the lack of first letter capitalized, it is
input and not Input or even qx.ui.decoration.Input or some other
package)
So I can't apply the pattern "widgetInstance.getDecorator()
instanceof" since this decorator instance look like unknown : input.
For example, I'm not able to find in the doc that input decorator.
Finally, I'm still unable to draw a red line around my widgets.
Can I add/remove decorator without breaking theme ? I was thinking to
add/remove dynamically a Single decorator instance to the widget
candidate.
Is there another direction/idea that would not involve decorator to
just draw red line around widget ?
On 24 Feb 2009, at 15:43, Alexander Back wrote:
> Hi Jean-Baptiste,
>
> Jean-Baptiste BRIAUD -- Novlog wrote:
>> If I understood correctly the API, any widget have a getDecorator()
>> method. It return "at least" a iDecorator instance.
>> Unfortunatly, I can't see how to change the border on iDecorator,
>> except maybe the tint method, but I have no idea witch element to
>> provide ...
> "iDecorator" is simply the Interface every decorator class has to
> implement. The API should read "you get an instance which is
> implements
> the interface 'iDecorator'".
>
>> On the other hand, I also see the classes like Single, Double,
>> Uniform, ... decorators, but I just don't know witch one will I
>> encounter on a given widget...
>> On Single, I see this property : color (Property group to set the
>> border color of all sides) but how to esure Uniform will always be
>> the
>> widget's border ?
> The answer is: you can't. At least not in a way that you call
> "getDecorator" on a widget and can be sure you have an "Uniform"
> decorator. You have to check for the decorator instance and modify
> only
> the border at decorators which are capable of.
>
>> Maybe I forgot to mention one point : I'm inside a generic method
>> where all I know is that a widget parameter is a widget but it could
>> be a table, a textarea, a textfield, any selectbox subclass, ...
> Then you have to check for them as I already mentioned.
>
> --snip--
> if (widgetInstance.getDecorator() instanceof qx.ui.decoration.Uniform)
> {
> // code for uniform decorators
> }
> // etc.
> --snip--
>
> cheers,
> Alex
>
>>
>> On 24 Feb 2009, at 14:06, thron7 wrote:
>>
>>> the most direct way would be to retrieve the current decorator of
>>> the
>>> desired element (with .getDecorator()), and set its border color to
>>> red.
>>>
>>> thomas
>>>
>>> Jean-Baptiste BRIAUD -- Novlog wrote:
>>>> Hi,
>>>>
>>>> I'd like to add a red border to some field (in case of inproper
>>>> user
>>>> input) but I though it might be a bad idea to change the decorator
>>>> since I don't have time for implementing my own decorator right
>>>> now.
>>>> Also, it won't be what I want to change the foreground or
>>>> background
>>>> color ...
>>>>
>>>> Any idea ?
>>>>
>>>> Thanks !
>
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