I haven't tried this, but you might be able to get it working via .call
or .apply
== cut ==
add: function(child, options) {
this.__content.add(child, options);
},
__containerAdd: function(child, options) {
this.baseClass.add.call(this, child, options);
}
== cut ==
As I said I haven't tested it but I think that should work.
Or looking at the code perhaps this:
__containerAdd: function(child, options) {
this.add.base.call(this, child, options);
}
Hope that helps,
Matt
Sebastian Fastner wrote:
> Hi,
>
> is there any easy way to access member methods of the base class? I like
> to write a new add-Function that does other things than the base add
> class, but on the other hand I still need access to the base add function.
>
> == cut ==
> add: function(child, options, toBase) {
> if (toBase) {
> this.base(arguments, child, options);
> } else {
> this.__content.add(child, options);
> }
> }
> == cut ==
>
> The above source shows an extended Composite class and the way I do it
> now, but I think it's no beauty solution :)
> If I use the add method like an composite add method (with 2 arguments)
> the new add method is called, otherwise the old method that should be
> accessible is called if I call it with 3 arguments (third parameter is
> true).
>
> I like to have something like
> == cut ==
> add: function(child, options) {
> this.__content.add(child, options);
> },
> __containerAdd: function(child, options) {
> this.baseClass.add(child, options);
> }
> == cut ==
>
> The art of writing software :)
>
> Thanx,
> Sebastian
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