Finaly, i've failed using qx.eventRegistration, but i succeed using
something like this :
var onInputEvent = function(ev) {
if (ev.getType() == 'blur' || ev.getKeyIdentifier() == 'Enter') {
doSomething();
}
}
textField.addListener('keypress', onInputEvent);
textField.addListener('blur',onInputEvent);
2013/5/23 franck34 <[email protected]>
>
> Got error
> No dispatcher can handle event of type keypress on qx.ui.form.TextField
>
> Thanks Derrell, i know where to go deeper ;)
>
>
> 2013/5/23 Derrell Lipman <[email protected]>
>
>> On Thu, May 23, 2013 at 2:25 PM, franck34 <[email protected]> wrote:
>>
>>>
>>> Hi the list.
>>>
>>> A day without mail ? not possible :)
>>>
>>> i've got
>>>
>>> textField.addListener('keypress',function(ev) {
>>> if (ev.getKeyIdentifier() == 'Enter') {
>>> doSomething();
>>> });
>>>
>>>
>>> and i'd like to add something like
>>>
>>> textField.addListener('blur',function(ev) {
>>> // blur event, let's do the same thing as the user type 'Enter' key
>>> textField.fireEvent('keypress',qx.event.type.KeySequence, args); //
>>> HERE IS ARGS
>>> });
>>>
>>
>> You can probably do something like this, which I haven't tested and
>> likely doesn't work quite correctly, but should at least point you in the
>> right direction:
>>
>> textField.addListener('blur', function(ev) {
>> var Registration = qx.event.Registration;
>> var e = Registration.createEvent('keypress', qx.event.type.KeySequence,
>> [ { keyCode : 13 }, textField, 'Enter' ]);
>> Registration.dispatchEvent(textField, e);
>> }
>>
>> Derrell
>>
>>
>>
>
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