Just call
popup.show() when page fires the "appear" event. That should do the trick.
The popup has a internal logic which makes sure, the popup always finds the
best position.
There is no easy way to disable that logic.
For your third problem you can use the property
hideOnBlockerTap
http://demo.qooxdoo.org/current/apiviewer/#qx.ui.mobile.dialog.Popup
With this, you can decide whether it hides on parent tap or not.
Greetz Christopher
Am 16.07.2014 um 12:48 schrieb Dragonheart
<dragonheart...@gmail.com<mailto:dragonheart...@gmail.com>>:
Hello! I have a mobile navigation page and a popup (not modal) anchored to an
image. Here's a short example:
var whiteIcon = new qx.ui.mobile.basic.Image(image);
this.getContent().add(whiteIcon);
var label = new qx.ui.mobile.basic.Label("labelOnPopup");
var popup = new qx.ui.mobile.dialog.Popup(label, whiteIcon);
popup.show();
I need it to be shown always (I wanna put there an amount of unread messages
for messages button in main menu), so I have a popup.show() method called in
the end of page initialization. Nevertheless, on page show it has left:0;
top:0 coords, like on image:
<http://qooxdoo.678.n2.nabble.com/file/n7585973/menu1.png>
But after any page resize it anchors as needed:
<http://qooxdoo.678.n2.nabble.com/file/n7585973/menu2.png>
Why does it come so and how can I fix it?
Also, after different page resize it may change it's position being on top
or under the element it is anchored to. Is there a way to always attach it
to the top for example?
Last problem is - it auto hides after page scrolling. Is there a way to make
it being always shown without making it modal?
I'll be glad for any advise! Thanks! Regards!
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