See also
qx.string.firstUp() and perhaps qx.lang.String.capitalize(),
qx.lang.String.camelCase()
Cheers,
Fritz
P.S.: Is your application publically accessible? Just curious ...
On Mon, 16 Feb 2015, Dietrich Streifert wrote:
> Hi Matt,
>
> the simpliest solution would be to write:
>
> var theRawPropertyID = 'dewpoint';
>
> var methodName = 'get'+capitaliseFirstLetter(theRawPropertyID);
> if(object[methodName]) {
> value = object[methodName].call(object);
> return value;
> } else {
> return null;
> }
>
> where capitaliseFirstLetter is a yet to write function
> (http://stackoverflow.com/questions/1026069/capitalize-the-first-letter-of-string-in-javascript)
>
> Regards
> Dietrich
>
> Am 16.02.2015 um 01:00 schrieb Matt Davis - NOAA Federal:
>> Hi Qooxdoo team and contributors,
>>
>> I use Qooxdoo in relation to a massive project of the U.S. National Weather
>> Service. We're not exactly new to Qooxdoo, we've been using qx since 1.x,
>> and our frontend is around 875k lines. Your project is outstanding, and
>> helping to protect the public. Thank you!
>>
>> I've run into something likely above my knowledge level, and seem to be
>> getting results I cannot debug.
>>
>> We have a qx object model of a weather/earth science observation. It may
>> have some number of several hundred possible properties.
>>
>> I need to determine if the property exists, and if so, whether it meets
>> certain criteria.
>>
>> I've read all I can on how this works and am still baffled. In some cases,
>> I can have results of which a console.log of the typeof returns nothing,
>> not null, not undefined, just nothing. This is throwing our various
>> conditionals into fits. I'd thought I'd fixed it with catching the
>> qxobject.get(element) error to determine existence, but this too is
>> throwing strange results. I have tried the 'in' operator and the
>> 'hasOwnProperty' method without success.
>>
>> The basic code is something like thing this. Element would be the raw
>> property ID. For instance, if the object has a 'getDewpoint()' method,
>> element would be 'dewpoint'.
>>
>> try {
>> if (object.get(element)) {
>> value = object.get(element);
>> return value;
>> } else {
>> // No element assigned
>> return null;
>> } catch(error) {
>> // It appears element was not set on object, so also return null
>> return null;
>> }
>>
>> I'm sure I'm missing something here. Consider several hundred observations
>> being sent through a member function
>> encasing the above code. As a programmer, I'd expect either the value or
>> null, but logging it every way I know how shows
>> it justing "skipping" values with no element.
>>
>> I'm hoping someone can enlighten me on my misunderstanding of this.
>>
>> Thank you much,
>> Matt
>>
>> --
>> /Iris, iNWS, and Impact Catalog Technical Lead/
>> /OS&T/MDL/DAB/
>> La Crosse, Wisconsin
>>
>>
>>
>>
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>
>
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