Looking at the source code for qx.Class, the mixin constructor is called as
follows:
mixins[i].$$constructor.apply(this,arguments);
This looks to me like 'this' in the constructor will be the instance of the
class doing the mixing in (include), not the mixin itself. If that's the
case, you can do:
hash = qx.core.ObjectRegistry.toHashCode(this);
to get the hash of the including, not included, class instance.
You should also be able to get the class name of 'this' with:
this.toString().replace(/\[.*/, "")
Hope that helps.
Derrell
On Wed, Dec 23, 2015 at 10:35 AM Dietrich Streifert <
dietrich.streif...@googlemail.com> wrote:
> Ah, OK. Thank you Derrell.
>
> Then I have to use something else to make this work.
>
> I need a mechanism which initializes some class specific static hash
> within the mixin, depending on the class the mixin is included to.
> After initialization of the hash, which is finished after the first
> instantiation of the class, the hash should be used by any subsequent
> instance.
> But the hash has to be specific to that class.
>
> One possibility would be to have a hash of hashes within the mixin, which
> is specific to the class where the mixin is included to.
> But this assumes that the mixin is capable of retrieving the class to
> which it is mixed in.
>
>
>
>
> Am 23.12.2015 um 16:08 schrieb Derrell Lipman:
>
> No, sorry, singleton is the opposite of what you want. Just some other
> regular class.
>
> Derrell
>
>
> On Wed, Dec 23, 2015 at 10:07 AM Derrell Lipman <
> derrell.lip...@unwireduniverse.com> wrote:
>
>> I don't think you can do that. The static is part of the mixin, it's not
>> per whatever it's mixed in to. Maybe you want to create a singleton class
>> to do that?
>>
>> Derrell
>>
>>
>> On Wed, Dec 23, 2015 at 10:03 AM Dietrich Streifert <
>> dietrich.streif...@googlemail.com> wrote:
>>
>>> Hi Derrell,
>>>
>>> but I want myhash to be specific to the class where the mixin is mixed
>>> in.
>>>
>>> So if I mixin to myapp.A and also to myapp.B the myhash static should be
>>> different for each class A and B.
>>>
>>>
>>> Am 23.12.2015 um 15:58 schrieb Derrell Lipman:
>>>
>>> Static members are accessed in exactly the same way regardless of
>>> whether they're in a mixin or not. In this case, you'd access
>>> "myapp.MMixin.myhash" because myhash is a static of the mixin itself.
>>>
>>> Derrell
>>>
>>>
>>> On Wed, Dec 23, 2015 at 9:52 AM Dietrich Streifert <
>>> dietrich.streif...@googlemail.com> wrote:
>>>
>>>> Hi all,
>>>>
>>>> if I have a mixin like this:
>>>>
>>>> qx.Mixin.define("myapp.MMixin",
>>>> {
>>>> statics : {
>>>> myhash: {}
>>>> },
>>>>
>>>> members: {
>>>> mymethod : function() {
>>>> this.self(arguments).myhash.foo = 'bar'; // this does not work
>>>> !!!!
>>>>
>>>> this.constructor.myhash.foo = 'bar'; // this does not work !!!!
>>>> }
>>>> }
>>>> });
>>>>
>>>> How do I access the static member myhash? The code above does not work!
>>>>
>>>> The mixin is of course used via include in another class.
>>>>
>>>> Any help would be great!
>>>>
>>>> Regards
>>>> Dietrich
>>>>
>>>
>>>
>
> ------------------------------------------------------------------------------
> _______________________________________________
> qooxdoo-devel mailing list
> qooxdoo-devel@lists.sourceforge.net
> https://lists.sourceforge.net/lists/listinfo/qooxdoo-devel
>
------------------------------------------------------------------------------
_______________________________________________
qooxdoo-devel mailing list
qooxdoo-devel@lists.sourceforge.net
https://lists.sourceforge.net/lists/listinfo/qooxdoo-devel
