> The name of the signal is the name of the object. In this case, you have > named your signal 'e'. If you want to make a signal called colorChanged, > do the following: > > Signal1<String> colorChanged = new Signal1<String>();
Wow, I was really close! I'm impressed with myself, given this is the first time I've ever tried to use Java generics. :) > Signals must be declared as members of your class. I'm guessing this is > the reason for your run time exception (was the message of the run time > exception "Signals must be declared as members of QSignalEmitter > subclasses", if so then this is your problem.) Your guess was correct - a quick tweak and it's working correctly. Thanks. _______________________________________________ Qt-jambi-interest mailing list [email protected] http://lists.trolltech.com/mailman/listinfo/qt-jambi-interest
