In a message dated 1/6/03 12:42:25 AM, [EMAIL PROTECTED] writes:

<<
> Even if the voltage, due to data transmission is only 1 volt, if it is 
> a
> "+" (positive) 1 volt and you put it to a terminal that is expecting a
> "-" (negative) 1 volt, it will smoke, maybe just a little or maybe a
> lot.  If it doesn't smoke it could just render a few of the component 
> in the circuit inoperative by shorting out.  Like no work anymore.

I'm a self-taught networker. I have wired a few cables up wrong (in the 
beginning at least) and never managed to blow any of my kit up. I would have 
thought equipment would have been built with idiot tolerance for reversed 
voltages, I know a lot of other stuff is.
>>

Both wrong. But the first is more wrong than the second.

If a single-ended circuit, there is only +5 volts and +5 volts Return (AKA, 
Ground).

Place +5 volts on a pin which is positive true logic, then that pin sees "+", 
ON, "1", whatever; place Ground on that same pin and that pin sees "-", OFF, 
"0", whatever.

Place +5 volts on a pin which is negative true logic (such as a SCSI-N bus), 
then that pin sees "-", OFF, "0", whatever; place Ground on that same pin and 
that pin sees "+", ON, "1", whatever.

If a differential circuit (such as a SCSI-LVD bus), there is only + several 
hundred millivolts with respect to a reference, and - several hundred 
millivolts with respect to that same reference.

If the non-dotted terminal is positive with respect to the dotted terminal, 
then the circuit sees "+", ON, "1", whatever; if the non-dotted terminal is 
negative with respect to the dotted terminal, then the circuit sees "-", OFF, 
"0", whatever.

Many circuits, contain protection for intentionally reversed voltages.


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