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On 21.06.2016 23:54, Arqwer wrote:
> How "quick" any of available super PCs (10,649,60 cores, 125,435. TFLOP/S
>> )  can find the password (e.g 8-16 chars) encrypted with Qubes default 
>> settings cryptsetup?
>> 
> 
> Encryption is the hardest part of chain. If the passphrase is long 
> enough.If password is 16 random lowercase and uppercasr letters, then it
> is 52^16 combinations, it is about 10^27. If you can crack 100 Peta 
> passwords/S, then it will take 10^(27-17) = 10^(10) seconds to brute the 
> password, which is 316 years. (Really expectation is half of it, so 158 
> years on average). Of course, if those letters are not "Password12345678".
> 
> How can we improve security to prevent this?
> 
> 
> If 316 years is not enough, than you can add one more character, to make
> it 16 thousands of years!


Most of those projections about how many years brute forcing a passphrase with
that many bits of entropy may take completely ignore one key aspect, especially
when you are talking about hundreds of years and that is technical advance and
Moore's law. So to be realistic, you would need to take that into
consideration.

Refer to:

*
https://crypto.stackexchange.com/questions/1815/how-to-account-for-moores-law-in
- -estimating-time-to-crack

- --
Live long and prosper
Robin `ypid` Schneider
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