On Thu, 13 Dec 2018 20:31:29 +0100
799 <one7tw...@gmail.com> wrote:
> Hello Chris,
>
> On Wed, 12 Dec 2018 at 22:52, Chris Laprise <tas...@posteo.net> wrote:
>
> > But here's how you could start the loop:
> > qvm-ls --running -O name | (read line; while read line; do qvm-run
> > -p $line 'your vm command goes here'; done)
> > [...]
> >
>
> thanks for the hint.
> I tried to run the following command which gives me a list of all
> running VMs (just to get the loop right):
> qvm-ls --running -O name --raw-data | (read line; while read line; do
> echo $line; done)
> In my case:
> my-untrusted
> my-vault
> sys-firewall
> sys-net
> sys-usb
>
> The command to get the information about the swap usage from a VM
> (here named APPVMNAME can be shown by running the following command
> in dom0:
>
> echo APPVMNAME = `qvm-run --pass-io APPVMNAME "free" | tail -n +3 |
> gawk '{ print $3 }'`
>
> But when I bring both peaces together I only get one result back, not
> the result for all AppVMs
>
> qvm-ls --running -O name --raw-data | (read line; while read line; do
> echo $line `qvm-run --pass-io $line "free" | tail -n +3 | gawk
> '{ print $3 }'` ; done)
>
> Output in my case:
> my-untrusted 256
>
> So the output is only showing the output for one VM.
> I don't understand why this is happening.
>
> - O
>
Hi,
I can't figure out why the code above only returns the first VM's
result, but the following code works for me :-
for i in `qvm-ls --running -O name --raw-data|grep -v dom0`;
do
echo $i = `qvm-run --pass-io $i "free"| tail -n +3 | gawk '{print
$3 }'`;
done
Mike.
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