On Mon, 18 Jul 2005 22:54:41 +0100, David Woolley wrote: > In article <[EMAIL PROTECTED]>, > Serge Bets <[EMAIL PROTECTED]> wrote: > >> Sorry again I feel I don't understand. Do you mean the unfair duration >> of low amplitude pulse being only 10% of a period, while high amplitude >> is 90%, makes the filter detect faster one edge than the other? > > That might be a contributory factor (by making it more difficult to > calculate the correct slicing level), but what I really mean is that the > edges are really slopes (actually curves) and if, say, the decision > voltage is less than halfway between the high and low voltage levels, > a transition from low to high will be detected early and one from > high to low will be detected late.
The thing is even if the filter in the module has the decision level at the mid point, the serial port *IS* asymmetric. It is swinging between about 10~12V and 0V with the change over point at about ~1.5V. JAB. -- Jonathan A. Buzzard Email: jonathan (at) buzzard.me.uk Northumberland, United Kingdom. Tel: +44 1661-832195 _______________________________________________ questions mailing list [email protected] https://lists.ntp.isc.org/mailman/listinfo/questions
