David Woolley wrote: > [email protected] wrote: > >> In the case below, will server 3 be treated as a falseticker because >> its offset lies outside the dispersion interval of the other two >> servers even though there is some intersection between its dispersion >> and that of server 2. > > That's basically why I won't be convinced by the four server argument > until I've checked the actual code. I seem to remember that there is an > additional constraint, namely that the actual measurement must fall > within the intersection. > >> 1 >> |--------+--------| >> 2 >> |----------+----------| >> 3 |------------+------------| >>
It's the other way around. The interval is expanded to include the mid-points. So, even though the overlap between server 2 and 3 is that small section, the interval actually used must include their mid-points (i.e. their offsets) so the interval used in the downstream calculations is the offset of server 2 through the offset of server 3. _______________________________________________ questions mailing list [email protected] https://lists.ntp.org/mailman/listinfo/questions
