Hin-Tak Leung wrote:
> Martin Maechler wrote:
>
>>>>>>>"Hin-Tak" == Hin-Tak Leung <[EMAIL PROTECTED]>
>>>>>>> on Fri, 18 Nov 2005 16:38:28 +0000 writes:
>>
>>
>> Hin-Tak> Your own fault. See below. It is basic LaTeX and any LaTeX person
>> Hin-Tak> can tell you the answer...(most probably haven't bothered...)
>>
>>No. Whereas I partly agree that it's Ross ``fault'' trying to
>>use too smart LaTex (and using outdated \bf instead of \mathbf),
>>;-)
>>
>>The bug is really there, since we are talking about the Rd "language",
>>not LaTeX, an in Rd, \eqn and \deqn are defined to have either
>>one or two arguments -- where Ross used the 2-argument version
>>correctly (in principle at least) --> See the manual "Writing R
>>Extensions".
>
>
> Forgive me for not reading R-ext carefully, but Ross's Rd code is
> still "obviously" wrong in the lights of the two-argument \eqn:
> (really doesn't differ from the 1-arg interpretaion of \eqn)
>
> \eqn{{\bf\beta}_j}{\bf\beta}_jnormal-bracket5bracket-normal{b(j)}
No, that is the output after conversion, please read the original
poster's mail more carefully.
Uwe Ligges
> In other words,
> \eqn{...}{...}_...
>
> and the "_" is still outside of any maths environment, which is most
> probably not Ross's intention.
>
>
>>
>> >> Full_Name: Ross Boylan
>> >> Version: 2.2.0
>> >> OS: Linux
>> >> Submission from: (NULL) (65.175.48.58)
>> >>
>> >>
>> >> \eqn{{\bf\beta}_j}{b(j)} in my .Rd file produces this error
>>
>> >> --------------------------------------------
>> >> ! Missing $ inserted.
>> >> <inserted text>
>> >> $
>> >> l.7 \eqn{{\bf\beta}_j}{\bf\beta}_jnormal-bracket5bracket-normal{b(j)}
>>
>> Hin-Tak> \eqn{{\bf\beta}_j} is already syntactically complete, so latex
>> Hin-Tak> complains the next "_" is not in maths mode, and automatically
>> Hin-Tak> switch into maths mode for you (the $ inserted message) You have
>> Hin-Tak> to match all the braces - you need 3 right-braces after \eqn,
>> Hin-Tak> like this, at least:
>>
>> Hin-Tak> \eqn{ { {\bf\beta
>> Hin-Tak> }_j
>> Hin-Tak> }
>> Hin-Tak> {\bf\beta
>> Hin-Tak> }_ ....
>> Hin-Tak> {b(j)
>> Hin-Tak> }
>> Hin-Tak> }
>
>
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