The code has
s = INT_MAX;
for (i = 0; i < n; i++) {
if (x[i] != NA_INTEGER) {
if (s > x[i]) {
s = x[i];
if(!updated) updated = 1;
}
}
else if (!narm) {
if(!updated) updated = 1;
*value = NA_INTEGER;
return(updated);
}
}
*value = s;
so it ignores the initial value INT_MAX (updated is not set). Fairly easy
to fix ... done for 2.3.0.
There's a parallel problem with -.Machine$integer.max, also fixed.
On Thu, 30 Mar 2006, [EMAIL PROTECTED] wrote:
> Full_Name: Martin Schlather
> Version: 2.2.0 and alpha 2.3.0 (06/3/29)
> OS: Linux (x86_64 and Intel)
> Submission from: (NULL) (139.11.183.106)
>
>
>> min(.Machine$integer.max, 10^20)
> [1] 1e+20
>
>> min(as.integer(.Machine$integer.max), 10^20)
> [1] 1e+20
>
>
> but
>> min(.Machine$integer.max + 0, 10^20)
> [1] 2147483647
>
>> min(as.integer(.Machine$integer.max - 1), 10^20)
> [1] 2147483646
>
>> min(as.double(.Machine$integer.max), 10^20)
> [1] 2147483647
>
> Cheers, Martin
>
> ______________________________________________
> R-devel@r-project.org mailing list
> https://stat.ethz.ch/mailman/listinfo/r-devel
>
>
--
Brian D. Ripley, [EMAIL PROTECTED]
Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/
University of Oxford, Tel: +44 1865 272861 (self)
1 South Parks Road, +44 1865 272866 (PA)
Oxford OX1 3TG, UK Fax: +44 1865 272595
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