On Fri, 7 Jul 2006, hadley wickham wrote: > I would like to take this: > > .img(plot(1:10), filename="a")
I presume from your title that you want to take foo <- parse(text='.img(plot(1:10), filename="a")') ? That's an expression. In which case > foo[[1]][[2]] plot(1:10) (first expression which a call, and calls are symbol, arg1, arg2 ...). > > and produce > > plot(1:10) > > ie. whenever .img is used, I want to take the first argument and throw > away everything else. > > (I am trying to produce a Sweave like environment in which I can apply > certain functions, but not have them displayed in the output) > > I think I should be able to do it using substitute, but I don't know > how to operate on language objects. Any hints would be appreciated. > > Thanks, > > Hadley > > ______________________________________________ > R-devel@r-project.org mailing list > https://stat.ethz.ch/mailman/listinfo/r-devel > > -- Brian D. Ripley, [EMAIL PROTECTED] Professor of Applied Statistics, http://www.stats.ox.ac.uk/~ripley/ University of Oxford, Tel: +44 1865 272861 (self) 1 South Parks Road, +44 1865 272866 (PA) Oxford OX1 3TG, UK Fax: +44 1865 272595 ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel
