> PROTECT(y=x); and This has no sense as y is just the same pointer as x. By doing this you did not create any new data, if you modify y, x will be modified. y does not need protection as x is probably protected.
> PROTECT (y = duplicate(x)); ? This will allocate new memory for data in x and copy data over there. This is correct, modifying y will not modify x. And y needs protection as it is newly allocated. > PROTECT(y = duplicate(x)); > PROTECT(z = duplicate(VECTOR_ELT(y,2))); It is not clear what you want to achieve by this. z will not be part of y any more > PROTECT(y=duplicate(x)); > PROTECT(z = VECTOR_ELT(y,2)); The correct way would be PROTECT(y=duplicate(x)); z = VECTOR_ELT(y,2); as you do not need to protect z, it is done by protecting y > And if I did create a duplicate, is there a way to destroy it manually > before the end of the function, rather than rely on on the R garbage > collector? Not that I know about. Best, Oleg -- Dr Oleg Sklyar | EBI-EMBL, Cambridge CB10 1SD, UK | +44-1223-494466 ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel
