A small PS:
John Chambers wrote:
Along the line, notice that both R_pow and pow give 0^0 as 1. (Just at
a guess, C might give 0^-0 as Inf, but I don't know how to test that in R.)
I tried a little harder, and apparently the guess is wrong. It seems
that pow(0, -0) is 1 in C. Would seem better to either have pow(0,0)
and pow(0,-0) both be NaN or else 1 and Inf, but ...
John
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