Hi, Please consider the following :
x = c(1,3,NA,5) y = c(2,NA,4,1) min(x,y,na.rm=TRUE) # ok [1] 1 max(x,y,na.rm=TRUE) # ok [1] 5 sum(x,y,na.rm=TRUE) # ok [1] 16 pmin(x,y,na.rm=TRUE) # ok [1] 1 3 4 1 pmax(x,y,na.rm=TRUE) # ok [1] 2 3 4 5 psum(x,y,na.rm=TRUE) [1] 3 3 4 6 # expected result Error: could not find function "psum" # actual result I realise that + is already like psum, but what about NA? x+y [1] 3 NA NA 6 # can't supply `na.rm=TRUE` to `+` Is there a case to add psum? Or have I missed something. This question survived when I asked on Stack Overflow : http://stackoverflow.com/questions/13123638/there-is-pmin-and-pmax-each-taking-na-rm-why-no-psum And a search of the archives found that has Gabor has suggested it too as an aside : http://r.789695.n4.nabble.com/How-to-do-it-without-for-loops-tp794745p794750.html If someone from R core is willing to sponsor the idea, I am willing to write, test and submit the code for psum. Implemented in a very similar fashion to pmin and pmax. Or perhaps it exists already in a package somewhere (I searched but didn't find it). Matthew ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel