I believe that for a list as.character() applies deparse() to each element
of the list. deparse() does not preserve NA-ness, as it is intended to
make text that the parser can read.
> str(as.character(list(Na=NA, LglVec=c(TRUE,NA),
Function=function(x){x+1})))
chr [1:3] "NA" "c(TRUE, NA)" "function (x) \n{\n x + 1\n}"
Bill Dunlap
TIBCO Software
wdunlap tibco.com
On Sat, Jan 20, 2018 at 7:43 AM, Patrick Perry <ppe...@stern.nyu.edu> wrote:
> As of R Under development (unstable) (2018-01-19 r74138):
>
> > as.character(list(NA))
> [1] "NA"
>
> > is.na(as.character(list(NA)))
> [1] FALSE
>
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