Kia Ora Let's say we have: "myreplacementfunction<-" = function (..., value) { call = sys.call () print (as.list (call) ) 0 }
Then we call: x = 0 myreplacementfunction (x, y, z) = 0 It will return: [[1]] `myreplacementfunction<-` [[2]] `*tmp*` [[3]] y [[4]] z $value <promise: 0x06fb6968> There's two problems here. Firstly, x has to be defined otherwise we get an error message. Secondly, the first argument is returned as *tmp*. Both are incorrect. It should be possible to call the function without defining x. And it should return x rather than *tmp*. In other words, replacement function calls should be the same as other function calls. Although it gets y and z right. kind regards Abs ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel