I have encountered a behavior of R’s JIT compiler that I can’t quite figure out. Consider the following code:
f_global <- function(x) { for(i in 1:10000) x <- x + 1 x } f_env <- local({ function(x) { for(i in 1:10000) x <- x + 1 x } }) compiler::enableJIT(3) bench::mark(f_global(0), f_env(0)) # 1 f_global(0) 103µs 107.61µs 8770. 11.4KB 0 4384 0 # 2 f_env(0) 1.1ms 1.42ms 712. 0B 66.3 290 27 Inspecting the closures shows that f_global has been byte-compiled while f_env has not been byte-compiled. Furthermore, if I assign a new environment to f_global (e.g. via environment(f_global) <- new.env()), it won’t be byte-compiled either. However, if I have a function returning a closure, that closure does get byte-compiled: f_closure <- (function() { function(x) { for(i in 1:10000) x <- x + 1 x } })() bench::mark(f_closure(0)) # 1 f_closure(0) 105µs 109µs 8625. 0B 2.01 4284 1 497ms What is going on here? Both f_closure and f_env have non-global environments. Why is one JIT-compiled, but not the other? Is there a way to ensure that functions defined in environments will be JIT-compiled? Thanks, Taras ______________________________________________ R-devel@r-project.org mailing list https://stat.ethz.ch/mailman/listinfo/r-devel